
Application Information (Continued)
The amount of output voltage ripple is determined by the
output capacitor C3 and the output current as shown in this
equation:
V
RIPPLE P-P =IOUT x (2xESRC3 + 1/[2x(fOSCxC3)])
Once again a larger capacitor with smaller ESR will give
better results.
+5V TO 5V REGULATED VOLTAGE CONVERTER
Another application in which the LM2682 can be used is for
generating a 5V regulated supply from a +5V unregulated
supply. This involves using an op-amp and a reference and
is connected as shown in
Figure 2. The LM358 op-amp was
chosen for its low cost and versatility and the LM4040-5.0
reference was chosen for its low bias current requirement.
Of course other combinations may be used at the designer’s
discretion to fit accuracy, efficiency, and cost requirements.
With this configuration the circuit is well regulated and is still
capable of providing nearly 10 mA of output current. With a 9
mA load the circuit can typically maintain 5% regulation on
the output voltage with the input varying anywhere from 4.5V
to the maximum of 5.5V. With less load the results are even
better. Voltage ripple concerns are reduced in this case since
the ripple at the output of the LM2682 is reduced at the
output by the PSRR of the op-amp used.
PARALLELING DEVICES
Any number of devices can be paralleled to reduce the
output resistance. As shown in
Figure 3, each device must
have its own pumping capacitors, C1 and C2, but only one
shared output capacitor is required. The effective output
resistance is the output resistance of one device divided by
the number of devices used in parallel. Paralleling devices
also gives the capability of increasing the maximum output
current. The maximum output current now becomes the
maximum output current for one device multiplied by the
number of devices used in parallel. For example, if you
parallel two devices you can get 20 mA of output current and
have half the output resistance of one device supplying 10
mA.
10099705
FIGURE 3. Paralleling Devices
LM2682
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